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一次遍历寻找数组中最大的前两个数
阅读量:364 次
发布时间:2019-03-05

本文共 476 字,大约阅读时间需要 1 分钟。

void PrintMax12(const vector
& br){ if (br.size() < 2) return; int max1 = br[0] > br[1] ? br[0] : br[1]; int max2 = br[0] > br[1] ? br[1] : br[0]; for (int i = 2; i < br.size(); ++i) { if (br[i] > max1) { max2 = max1; max1 = br[i]; } else if (br[i] > max2) { max2 = br[i]; } } cout << "max1: " << max1 << " max2: " << max2 << endl;}int main(){ vector
ar = { 56,34,100,23,78,90,12,45,67,89 }; PrintMax12(ar); return 0;}

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